๐ŸŽฐ Java Programing: Solution to Programming Exercise

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Answer to I need a very simple java code that plays blackjack and has a while loop. aces must be able to change between 1 and 11 t.


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I've tried to take the Blackjack game a little further, adding the ability to identify suits and specific face cards. while loops can lead to infinite loops, so be careful. Well JS is my first language (fair experience only in java and visual basic) and.


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Answer to I need a very simple java code that plays blackjack and has a while loop. aces must be able to change between 1 and 11 t.


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calls "displayInstructions" to tell the user how blackjack works: do /* do while loop to loop playing blackjack Java Program to find Sum of Elements in an Array.


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See the file moneyspinslots.site for more information. */ public The while loop ends when the user chooses to "Stand" or when the user goes over */ while.


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return true; } /* If neither player has Blackjack, play the game. The user gets a chance to draw cards (i.e., to "Hit"). The while loop ends when the user chooses to.


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blackjack java while loop

This is because in every if statement you break from the loop and do not enter it again. JohnMark13 JohnMark13 3, 1 1 gold badge 10 10 silver badges 26 26 bronze badges. My teacher does not really explain things and tells us to google it. It would be great if you could explain the concept. Visit chat. Asked 6 years, 9 months ago.

Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share read more. Podcast New tools for new times. If choice is 1 it can never be 2 in the same block of code.

Blackjack java while loop use of the break statements means that your loop performs a very limited function, more like an if. Why the developers who use Rust love it so much. Email Required, but never shown.

See my edit to the first block of code in my post. Stack Overflow works best with JavaScript enabled.

Edit in original post. See edit, also read The recommendations made by Mena. The problem I am having is I can not get the program to allow input after the first choice within the loop. Learn more. Mena Mena I am not familiar with a switch statement. Active 6 years, 9 months ago. Viewed 2k times. On breaking out of the loop you have no more code to run. What posts should be escalated to staff using [status-review], and how do Iโ€ฆ. If you google "java switch" you'll find this page right on top. For example if the player chooses to hit on their first turn, it works, but on their next turn I can not get the program to allow input. The Overflow Blog. Your problem is that you are literally taking the user's input only once. For every iteration of the loop you need to make sure you get correct input each time and only if they choose to hit get a card. This is because your code for handling your stay choice is now in your code for hit choice, look at the logic. Sign up using Email and Password. Doesn't it explain enough for you? Sign up or log in Sign up using Google. Related Hot Network Questions. I am not sure your program is breaking the way you think it is. Post as a guest Name. Sign up using Facebook. Thank you!. The only issue I am having now is when the player chooses to stay 2 ,the program still picks cards until it busts. This is my first year taking a programming class. This time when I choose to stay nothing is output at all. This is the revised code I have. Also, you should catch InputMismatchException s for unexpected input types, and allow the user to get out of the loop. The program will keep adding cards as all your card handling code needs to be in the following condition. I am trying to program a basic game of Blackjack. Everything you have said here has really helped. You have a lot of repetition, consider using a switch case on guess3 where 1 outputs the Ace statement 2 through 10 are all the same so, no break statements 'System. We're switching to CommonMark. Java Devil Java Devil 9, 7 7 gold badges 28 28 silver badges 41 41 bronze badges. If your loop worked your use of answer and hand variables means that you would never get a correct value each time around the loop just adding the original two values to the third value. Either store the cards in a list, or keep a cumulative score. I don't see where choice is being changed from within the loop. Currently this is not the case so your program with just add cards every time as you don't check what the user has chosen. Featured on Meta. What you need is a looping condition which is true until either the player busts or chooses to stay and don't break from the loop in every if statement, instead i think you might want to use continue. Altogether I would recommend: using the infinite loop as per above using Scanner nextLine instead of Scanner nextInt getting a String as a result checking for something starting with "q" or such like for the user wanting to quit otherwise, attempting to parse an Integer out of the String with Integer. Question feed. Active Oldest Votes. Also, I'd strongly recommend using a switch statement to categorize the Integer from the user, instead of the messy if-then-else.